How to Solve Simplification & Approximation Questions? Tips & Tricks


How to Solve Simplification & Approximation Questions? Tips & Tricks

How to Solve Simplification & Approximation Questions? In the Quantitative Aptitude section of the Bank exam consists of questions such as Simplification & Approximation. Usually the 1st question of Quants section of Bank PO and Clerk Exam is from Simplification and Approximation. It is a very important part of the Quantitative Aptitude section of Bank Clerk Exams. Usually 10-15 questions are expected from this topic and they usually take less than a minute to solve. This makes it the most important topic of Quant section.

Simplification, unlike its name, was not taught to us in a simple way but in a complicated way because of which we take long to solve Simplification Questions. But this smart method where you have to smartly use the digits in the units place will simplify this problem for you.

We are providing you Important Short Tricks for How to Solve Simplification & Approximation Questions? Which are usually asked in Bank Exams?

How to Solve Simplification & Approximation Questions?

How to Solve Simplification – Basic Rules of Simplification

1. Simplification BODMAS Rule – The best way to Simplify Questions

One of the primary techniques to solve simplification problems is BODMAS rule which is explained below.

B = Bracket

Order = (Powers, square roots, etc.)

D = Division

M = Multiplication

A = Addition

S = Subtraction

Simplification problems are solved by using the BODMAS technique. As per the BODMAS technique/rule we must first solve the numbers that have been given in the brackets, next to this, orders and powers are solved followed by Division, Multiplication, Addition and Subtraction.

Let us solve an example –

Example 1

18 + 22 / 11 * (18 / 3) 2 – 5

= 18 + 22 / 11 * 6 *2 – 5   (First solve the Brackets)

= 18 + 22 / 11 * 36 – 5   (then solve Exponents)

= 18 + 2 * 36 -5 (further attempt Division and Multiplication, left to right)

= 18 + 72 – 5    (finally Add and Subtract, Left to right)

= 90 – 5

= 85

2. To Solve Modulus of a Real Number

The Modulus (or the absolute value) of x is always either positive or zero, but never negative. For any real number x, the absolute value or modulus of x is denoted by |x| and is defined as

|x|= x {if x ≥ 0} and −x {if x < 0}

Example: Solve |8|

|8| = |-8|  = 8

3. Learn square roots up to 10

A simple trick to save time in the exam is to memorize square roots till 10. Square roots and cube roots can be a part of the simplification/approximation question. Remembering these values can help you save some time and reach the approximate value quickly.

Round off decimal numbers to nearest whole number

There is no shortcut to maths. Only ample practice and time-saving techniques can help. For solving long equations, first, convert the decimal to the nearest value. Further, simplify the equation (Applying criteria of BODMAS) given using new values that you have attained.

4. Let us apply this to an example –

 Solve 4433.764 – 2211.993 – 1133.667 + 3377.442

4433.764 = 4434
2211.993 = 2212
1133.667 = 1134
3377.442 = 3377

Now simplify, 4434 –  2212 – 1134 + 3377 = 4466

5. Look for a hidden value that can help simplify

The Bank exams are not just a test of your aptitude but also how tactfully you can manage your time. Every question has a hidden trick that if figured out, can make the question very simple. Look for such hints to save time.

Let’s see how we can decipher a hidden trick:

What approximate value will come in place of the mark (?) in the following question mark (?) in the following questions? You are not expected to calculate the exact value.

67.99% of 1401 – 13.99% of 1299 =?

a) 700        b) 720          c) 770            d) 800         e) 740

This looks like a very time-consuming question. Under time pressure you might skip it. Let’s see how this can be simplified:

We start by rounding off the values in 67.99 of 1401 – 13.99% of 1299

= 68 * 1400 – 14*1300

We are ignoring the % sign for the time being

(Here we have rounded off 1401 to 1400 to get 1400 in common in the 2 parts of the equation)

= 68* 1400 – 1400*13

[we have multiplied 14 by 100 to get 1400 and divided 1300 by 100 to get 13]

=1400*[68 – 13]

Now we bring back the % sign

=1400*55/100 = 770

Approximation of Square Roots

To simplify a square root, you can follow these steps:

Factor the number inside the square root sign.

If a factor appears twice, cross out both and write the factor one time to the left of the square root sign. If the factor appears three times, cross out two of the factors and write the factor outside the sign, and leave the third factor inside the sign. Note: If a factor appears 4, 6, 8, etc. times, this counts as 2, 3, and 4 pairs, respectively.

Multiply the numbers outside the sign.

Multiply the numbers left on the sign.

To simplify the square root of a fraction, simplify the numerator and simplify the denominator.

Click Here To Practice Simplification & Approximation Question

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